Integrand size = 23, antiderivative size = 214 \[ \int \frac {\sin ^5(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {\sqrt {b} \left (15 a^2+70 a b+63 b^2\right ) \arctan \left (\frac {\sqrt {a} \cos (e+f x)}{\sqrt {b}}\right )}{8 a^{11/2} f}-\frac {\left (3 a^2+14 a b+13 b^2\right ) \cos (e+f x)}{2 a^5 f}+\frac {(a+3 b) (3 a+5 b) \cos ^3(e+f x)}{12 a^4 b f}-\frac {\cos ^5(e+f x)}{5 a^3 f}-\frac {(a+b)^2 \cos ^7(e+f x)}{4 a^2 b f \left (b+a \cos ^2(e+f x)\right )^2}-\frac {b (a+b) (3 a+11 b) \cos (e+f x)}{8 a^5 f \left (b+a \cos ^2(e+f x)\right )} \]
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Time = 0.30 (sec) , antiderivative size = 214, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {4218, 474, 466, 1824, 211} \[ \int \frac {\sin ^5(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=-\frac {b (a+b) (3 a+11 b) \cos (e+f x)}{8 a^5 f \left (a \cos ^2(e+f x)+b\right )}+\frac {(a+3 b) (3 a+5 b) \cos ^3(e+f x)}{12 a^4 b f}-\frac {\cos ^5(e+f x)}{5 a^3 f}-\frac {(a+b)^2 \cos ^7(e+f x)}{4 a^2 b f \left (a \cos ^2(e+f x)+b\right )^2}+\frac {\sqrt {b} \left (15 a^2+70 a b+63 b^2\right ) \arctan \left (\frac {\sqrt {a} \cos (e+f x)}{\sqrt {b}}\right )}{8 a^{11/2} f}-\frac {\left (3 a^2+14 a b+13 b^2\right ) \cos (e+f x)}{2 a^5 f} \]
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Rule 211
Rule 466
Rule 474
Rule 1824
Rule 4218
Rubi steps \begin{align*} \text {integral}& = -\frac {\text {Subst}\left (\int \frac {x^6 \left (1-x^2\right )^2}{\left (b+a x^2\right )^3} \, dx,x,\cos (e+f x)\right )}{f} \\ & = -\frac {(a+b)^2 \cos ^7(e+f x)}{4 a^2 b f \left (b+a \cos ^2(e+f x)\right )^2}+\frac {\text {Subst}\left (\int \frac {x^6 \left (-4 a^2+7 (a+b)^2-4 a b x^2\right )}{\left (b+a x^2\right )^2} \, dx,x,\cos (e+f x)\right )}{4 a^2 b f} \\ & = -\frac {(a+b)^2 \cos ^7(e+f x)}{4 a^2 b f \left (b+a \cos ^2(e+f x)\right )^2}-\frac {b (a+b) (3 a+11 b) \cos (e+f x)}{8 a^5 f \left (b+a \cos ^2(e+f x)\right )}-\frac {\text {Subst}\left (\int \frac {-a b^2 (a+b) (3 a+11 b)+2 a^2 b (a+b) (3 a+11 b) x^2-2 a^3 (a+b) (3 a+11 b) x^4+8 a^4 b x^6}{b+a x^2} \, dx,x,\cos (e+f x)\right )}{8 a^6 b f} \\ & = -\frac {(a+b)^2 \cos ^7(e+f x)}{4 a^2 b f \left (b+a \cos ^2(e+f x)\right )^2}-\frac {b (a+b) (3 a+11 b) \cos (e+f x)}{8 a^5 f \left (b+a \cos ^2(e+f x)\right )}-\frac {\text {Subst}\left (\int \left (4 a b \left (3 a^2+14 a b+13 b^2\right )-2 a^2 (a+3 b) (3 a+5 b) x^2+8 a^3 b x^4+\frac {-15 a^3 b^2-70 a^2 b^3-63 a b^4}{b+a x^2}\right ) \, dx,x,\cos (e+f x)\right )}{8 a^6 b f} \\ & = -\frac {\left (3 a^2+14 a b+13 b^2\right ) \cos (e+f x)}{2 a^5 f}+\frac {(a+3 b) (3 a+5 b) \cos ^3(e+f x)}{12 a^4 b f}-\frac {\cos ^5(e+f x)}{5 a^3 f}-\frac {(a+b)^2 \cos ^7(e+f x)}{4 a^2 b f \left (b+a \cos ^2(e+f x)\right )^2}-\frac {b (a+b) (3 a+11 b) \cos (e+f x)}{8 a^5 f \left (b+a \cos ^2(e+f x)\right )}+\frac {\left (b \left (15 a^2+70 a b+63 b^2\right )\right ) \text {Subst}\left (\int \frac {1}{b+a x^2} \, dx,x,\cos (e+f x)\right )}{8 a^5 f} \\ & = \frac {\sqrt {b} \left (15 a^2+70 a b+63 b^2\right ) \arctan \left (\frac {\sqrt {a} \cos (e+f x)}{\sqrt {b}}\right )}{8 a^{11/2} f}-\frac {\left (3 a^2+14 a b+13 b^2\right ) \cos (e+f x)}{2 a^5 f}+\frac {(a+3 b) (3 a+5 b) \cos ^3(e+f x)}{12 a^4 b f}-\frac {\cos ^5(e+f x)}{5 a^3 f}-\frac {(a+b)^2 \cos ^7(e+f x)}{4 a^2 b f \left (b+a \cos ^2(e+f x)\right )^2}-\frac {b (a+b) (3 a+11 b) \cos (e+f x)}{8 a^5 f \left (b+a \cos ^2(e+f x)\right )} \\ \end{align*}
Result contains complex when optimal does not.
Time = 9.36 (sec) , antiderivative size = 1641, normalized size of antiderivative = 7.67 \[ \int \frac {\sin ^5(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {(a+2 b+a \cos (2 (e+f x))) \sec ^6(e+f x) \left (-900 a^{11/2} b^{3/2} \cos (e+f x)-109000 a^{9/2} b^{5/2} \cos (e+f x)-936000 a^{7/2} b^{7/2} \cos (e+f x)-2803072 a^{5/2} b^{9/2} \cos (e+f x)-3763200 a^{3/2} b^{11/2} \cos (e+f x)-1935360 \sqrt {a} b^{13/2} \cos (e+f x)-900 a^{11/2} b^{3/2} \cos (e+f x) \cos (2 (e+f x))+900 a^{9/2} b^{3/2} \cos (e+f x) (a+2 b+a \cos (2 (e+f x)))+24000 a^{7/2} b^{5/2} \cos (e+f x) (a+2 b+a \cos (2 (e+f x)))+43200 a^{5/2} b^{7/2} \cos (e+f x) (a+2 b+a \cos (2 (e+f x)))+225 a^5 \arctan \left (\frac {\left (-\sqrt {a}-i \sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2}\right ) \sin (e) \tan \left (\frac {f x}{2}\right )+\cos (e) \left (\sqrt {a}-\sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2} \tan \left (\frac {f x}{2}\right )\right )}{\sqrt {b}}\right ) (a+2 b+a \cos (2 (e+f x)))^2+115200 a^2 b^3 \arctan \left (\frac {\left (-\sqrt {a}-i \sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2}\right ) \sin (e) \tan \left (\frac {f x}{2}\right )+\cos (e) \left (\sqrt {a}-\sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2} \tan \left (\frac {f x}{2}\right )\right )}{\sqrt {b}}\right ) (a+2 b+a \cos (2 (e+f x)))^2+537600 a b^4 \arctan \left (\frac {\left (-\sqrt {a}-i \sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2}\right ) \sin (e) \tan \left (\frac {f x}{2}\right )+\cos (e) \left (\sqrt {a}-\sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2} \tan \left (\frac {f x}{2}\right )\right )}{\sqrt {b}}\right ) (a+2 b+a \cos (2 (e+f x)))^2+483840 b^5 \arctan \left (\frac {\left (-\sqrt {a}-i \sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2}\right ) \sin (e) \tan \left (\frac {f x}{2}\right )+\cos (e) \left (\sqrt {a}-\sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2} \tan \left (\frac {f x}{2}\right )\right )}{\sqrt {b}}\right ) (a+2 b+a \cos (2 (e+f x)))^2+225 a^5 \arctan \left (\frac {\left (-\sqrt {a}+i \sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2}\right ) \sin (e) \tan \left (\frac {f x}{2}\right )+\cos (e) \left (\sqrt {a}+\sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2} \tan \left (\frac {f x}{2}\right )\right )}{\sqrt {b}}\right ) (a+2 b+a \cos (2 (e+f x)))^2+115200 a^2 b^3 \arctan \left (\frac {\left (-\sqrt {a}+i \sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2}\right ) \sin (e) \tan \left (\frac {f x}{2}\right )+\cos (e) \left (\sqrt {a}+\sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2} \tan \left (\frac {f x}{2}\right )\right )}{\sqrt {b}}\right ) (a+2 b+a \cos (2 (e+f x)))^2+537600 a b^4 \arctan \left (\frac {\left (-\sqrt {a}+i \sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2}\right ) \sin (e) \tan \left (\frac {f x}{2}\right )+\cos (e) \left (\sqrt {a}+\sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2} \tan \left (\frac {f x}{2}\right )\right )}{\sqrt {b}}\right ) (a+2 b+a \cos (2 (e+f x)))^2+483840 b^5 \arctan \left (\frac {\left (-\sqrt {a}+i \sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2}\right ) \sin (e) \tan \left (\frac {f x}{2}\right )+\cos (e) \left (\sqrt {a}+\sqrt {a+b} \sqrt {(\cos (e)-i \sin (e))^2} \tan \left (\frac {f x}{2}\right )\right )}{\sqrt {b}}\right ) (a+2 b+a \cos (2 (e+f x)))^2-225 a^5 \arctan \left (\frac {\sqrt {a}-\sqrt {a+b} \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {b}}\right ) (a+2 b+a \cos (2 (e+f x)))^2-225 a^5 \arctan \left (\frac {\sqrt {a}+\sqrt {a+b} \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {b}}\right ) (a+2 b+a \cos (2 (e+f x)))^2+19200 a^{5/2} b^{5/2} \cos (e) \cos (f x) (a+2 b+a \cos (2 (e+f x)))^2-20352 a^{9/2} b^{5/2} \cos (e+f x) \cos (4 (e+f x))-115712 a^{7/2} b^{7/2} \cos (e+f x) \cos (4 (e+f x))-129024 a^{5/2} b^{9/2} \cos (e+f x) \cos (4 (e+f x))+2048 a^{9/2} b^{5/2} \cos (e+f x) \cos (6 (e+f x))+4608 a^{7/2} b^{7/2} \cos (e+f x) \cos (6 (e+f x))-384 a^{9/2} b^{5/2} \cos (e+f x) \cos (8 (e+f x))-19200 a^{5/2} b^{5/2} (a+2 b+a \cos (2 (e+f x)))^2 \sin (e) \sin (f x)-32496 a^{9/2} b^{5/2} \csc (e+f x) \sin (4 (e+f x))-252080 a^{7/2} b^{7/2} \csc (e+f x) \sin (4 (e+f x))-577024 a^{5/2} b^{9/2} \csc (e+f x) \sin (4 (e+f x))-403200 a^{3/2} b^{11/2} \csc (e+f x) \sin (4 (e+f x))\right )}{491520 a^{11/2} b^{5/2} f \left (a+b \sec ^2(e+f x)\right )^3} \]
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Time = 10.37 (sec) , antiderivative size = 190, normalized size of antiderivative = 0.89
method | result | size |
derivativedivides | \(\frac {-\frac {\frac {\cos \left (f x +e \right )^{5} a^{2}}{5}-\frac {2 a^{2} \cos \left (f x +e \right )^{3}}{3}-a \cos \left (f x +e \right )^{3} b +a^{2} \cos \left (f x +e \right )+6 a b \cos \left (f x +e \right )+6 b^{2} \cos \left (f x +e \right )}{a^{5}}+\frac {b \left (\frac {\left (-\frac {9}{8} a^{3}-\frac {13}{4} a^{2} b -\frac {17}{8} a \,b^{2}\right ) \cos \left (f x +e \right )^{3}-\frac {b \left (7 a^{2}+22 a b +15 b^{2}\right ) \cos \left (f x +e \right )}{8}}{\left (b +a \cos \left (f x +e \right )^{2}\right )^{2}}+\frac {\left (15 a^{2}+70 a b +63 b^{2}\right ) \arctan \left (\frac {a \cos \left (f x +e \right )}{\sqrt {a b}}\right )}{8 \sqrt {a b}}\right )}{a^{5}}}{f}\) | \(190\) |
default | \(\frac {-\frac {\frac {\cos \left (f x +e \right )^{5} a^{2}}{5}-\frac {2 a^{2} \cos \left (f x +e \right )^{3}}{3}-a \cos \left (f x +e \right )^{3} b +a^{2} \cos \left (f x +e \right )+6 a b \cos \left (f x +e \right )+6 b^{2} \cos \left (f x +e \right )}{a^{5}}+\frac {b \left (\frac {\left (-\frac {9}{8} a^{3}-\frac {13}{4} a^{2} b -\frac {17}{8} a \,b^{2}\right ) \cos \left (f x +e \right )^{3}-\frac {b \left (7 a^{2}+22 a b +15 b^{2}\right ) \cos \left (f x +e \right )}{8}}{\left (b +a \cos \left (f x +e \right )^{2}\right )^{2}}+\frac {\left (15 a^{2}+70 a b +63 b^{2}\right ) \arctan \left (\frac {a \cos \left (f x +e \right )}{\sqrt {a b}}\right )}{8 \sqrt {a b}}\right )}{a^{5}}}{f}\) | \(190\) |
risch | \(-\frac {{\mathrm e}^{5 i \left (f x +e \right )}}{160 a^{3} f}+\frac {5 \,{\mathrm e}^{3 i \left (f x +e \right )}}{96 a^{3} f}+\frac {{\mathrm e}^{3 i \left (f x +e \right )} b}{8 a^{4} f}-\frac {5 \,{\mathrm e}^{i \left (f x +e \right )}}{16 a^{3} f}-\frac {21 \,{\mathrm e}^{i \left (f x +e \right )} b}{8 a^{4} f}-\frac {3 \,{\mathrm e}^{i \left (f x +e \right )} b^{2}}{a^{5} f}-\frac {5 \,{\mathrm e}^{-i \left (f x +e \right )}}{16 a^{3} f}-\frac {21 \,{\mathrm e}^{-i \left (f x +e \right )} b}{8 a^{4} f}-\frac {3 \,{\mathrm e}^{-i \left (f x +e \right )} b^{2}}{a^{5} f}+\frac {5 \,{\mathrm e}^{-3 i \left (f x +e \right )}}{96 a^{3} f}+\frac {{\mathrm e}^{-3 i \left (f x +e \right )} b}{8 a^{4} f}-\frac {{\mathrm e}^{-5 i \left (f x +e \right )}}{160 a^{3} f}-\frac {b \left (9 a^{3} {\mathrm e}^{7 i \left (f x +e \right )}+26 a^{2} b \,{\mathrm e}^{7 i \left (f x +e \right )}+17 a \,b^{2} {\mathrm e}^{7 i \left (f x +e \right )}+27 a^{3} {\mathrm e}^{5 i \left (f x +e \right )}+106 a^{2} b \,{\mathrm e}^{5 i \left (f x +e \right )}+139 a \,b^{2} {\mathrm e}^{5 i \left (f x +e \right )}+60 b^{3} {\mathrm e}^{5 i \left (f x +e \right )}+27 a^{3} {\mathrm e}^{3 i \left (f x +e \right )}+106 a^{2} b \,{\mathrm e}^{3 i \left (f x +e \right )}+139 a \,b^{2} {\mathrm e}^{3 i \left (f x +e \right )}+60 b^{3} {\mathrm e}^{3 i \left (f x +e \right )}+9 a^{3} {\mathrm e}^{i \left (f x +e \right )}+26 a^{2} b \,{\mathrm e}^{i \left (f x +e \right )}+17 a \,b^{2} {\mathrm e}^{i \left (f x +e \right )}\right )}{4 a^{5} f \left (a \,{\mathrm e}^{4 i \left (f x +e \right )}+2 a \,{\mathrm e}^{2 i \left (f x +e \right )}+4 b \,{\mathrm e}^{2 i \left (f x +e \right )}+a \right )^{2}}+\frac {63 i \sqrt {a b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {a b}\, {\mathrm e}^{i \left (f x +e \right )}}{a}+1\right ) b^{2}}{16 a^{6} f}+\frac {35 i \sqrt {a b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {a b}\, {\mathrm e}^{i \left (f x +e \right )}}{a}+1\right ) b}{8 a^{5} f}-\frac {63 i \sqrt {a b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {a b}\, {\mathrm e}^{i \left (f x +e \right )}}{a}+1\right ) b^{2}}{16 a^{6} f}+\frac {15 i \sqrt {a b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {a b}\, {\mathrm e}^{i \left (f x +e \right )}}{a}+1\right )}{16 a^{4} f}-\frac {35 i \sqrt {a b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {a b}\, {\mathrm e}^{i \left (f x +e \right )}}{a}+1\right ) b}{8 a^{5} f}-\frac {15 i \sqrt {a b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {a b}\, {\mathrm e}^{i \left (f x +e \right )}}{a}+1\right )}{16 a^{4} f}\) | \(753\) |
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Time = 0.32 (sec) , antiderivative size = 579, normalized size of antiderivative = 2.71 \[ \int \frac {\sin ^5(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\left [-\frac {48 \, a^{4} \cos \left (f x + e\right )^{9} - 16 \, {\left (10 \, a^{4} + 9 \, a^{3} b\right )} \cos \left (f x + e\right )^{7} + 16 \, {\left (15 \, a^{4} + 70 \, a^{3} b + 63 \, a^{2} b^{2}\right )} \cos \left (f x + e\right )^{5} + 50 \, {\left (15 \, a^{3} b + 70 \, a^{2} b^{2} + 63 \, a b^{3}\right )} \cos \left (f x + e\right )^{3} - 15 \, {\left ({\left (15 \, a^{4} + 70 \, a^{3} b + 63 \, a^{2} b^{2}\right )} \cos \left (f x + e\right )^{4} + 15 \, a^{2} b^{2} + 70 \, a b^{3} + 63 \, b^{4} + 2 \, {\left (15 \, a^{3} b + 70 \, a^{2} b^{2} + 63 \, a b^{3}\right )} \cos \left (f x + e\right )^{2}\right )} \sqrt {-\frac {b}{a}} \log \left (-\frac {a \cos \left (f x + e\right )^{2} + 2 \, a \sqrt {-\frac {b}{a}} \cos \left (f x + e\right ) - b}{a \cos \left (f x + e\right )^{2} + b}\right ) + 30 \, {\left (15 \, a^{2} b^{2} + 70 \, a b^{3} + 63 \, b^{4}\right )} \cos \left (f x + e\right )}{240 \, {\left (a^{7} f \cos \left (f x + e\right )^{4} + 2 \, a^{6} b f \cos \left (f x + e\right )^{2} + a^{5} b^{2} f\right )}}, -\frac {24 \, a^{4} \cos \left (f x + e\right )^{9} - 8 \, {\left (10 \, a^{4} + 9 \, a^{3} b\right )} \cos \left (f x + e\right )^{7} + 8 \, {\left (15 \, a^{4} + 70 \, a^{3} b + 63 \, a^{2} b^{2}\right )} \cos \left (f x + e\right )^{5} + 25 \, {\left (15 \, a^{3} b + 70 \, a^{2} b^{2} + 63 \, a b^{3}\right )} \cos \left (f x + e\right )^{3} - 15 \, {\left ({\left (15 \, a^{4} + 70 \, a^{3} b + 63 \, a^{2} b^{2}\right )} \cos \left (f x + e\right )^{4} + 15 \, a^{2} b^{2} + 70 \, a b^{3} + 63 \, b^{4} + 2 \, {\left (15 \, a^{3} b + 70 \, a^{2} b^{2} + 63 \, a b^{3}\right )} \cos \left (f x + e\right )^{2}\right )} \sqrt {\frac {b}{a}} \arctan \left (\frac {a \sqrt {\frac {b}{a}} \cos \left (f x + e\right )}{b}\right ) + 15 \, {\left (15 \, a^{2} b^{2} + 70 \, a b^{3} + 63 \, b^{4}\right )} \cos \left (f x + e\right )}{120 \, {\left (a^{7} f \cos \left (f x + e\right )^{4} + 2 \, a^{6} b f \cos \left (f x + e\right )^{2} + a^{5} b^{2} f\right )}}\right ] \]
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Timed out. \[ \int \frac {\sin ^5(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\text {Timed out} \]
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Time = 0.27 (sec) , antiderivative size = 204, normalized size of antiderivative = 0.95 \[ \int \frac {\sin ^5(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=-\frac {\frac {15 \, {\left ({\left (9 \, a^{3} b + 26 \, a^{2} b^{2} + 17 \, a b^{3}\right )} \cos \left (f x + e\right )^{3} + {\left (7 \, a^{2} b^{2} + 22 \, a b^{3} + 15 \, b^{4}\right )} \cos \left (f x + e\right )\right )}}{a^{7} \cos \left (f x + e\right )^{4} + 2 \, a^{6} b \cos \left (f x + e\right )^{2} + a^{5} b^{2}} - \frac {15 \, {\left (15 \, a^{2} b + 70 \, a b^{2} + 63 \, b^{3}\right )} \arctan \left (\frac {a \cos \left (f x + e\right )}{\sqrt {a b}}\right )}{\sqrt {a b} a^{5}} + \frac {8 \, {\left (3 \, a^{2} \cos \left (f x + e\right )^{5} - 5 \, {\left (2 \, a^{2} + 3 \, a b\right )} \cos \left (f x + e\right )^{3} + 15 \, {\left (a^{2} + 6 \, a b + 6 \, b^{2}\right )} \cos \left (f x + e\right )\right )}}{a^{5}}}{120 \, f} \]
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Leaf count of result is larger than twice the leaf count of optimal. 781 vs. \(2 (194) = 388\).
Time = 0.47 (sec) , antiderivative size = 781, normalized size of antiderivative = 3.65 \[ \int \frac {\sin ^5(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\text {Too large to display} \]
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Time = 17.90 (sec) , antiderivative size = 255, normalized size of antiderivative = 1.19 \[ \int \frac {\sin ^5(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {{\cos \left (e+f\,x\right )}^3\,\left (\frac {b}{a^4}+\frac {2}{3\,a^3}\right )}{f}-\frac {\left (\frac {9\,a^3\,b}{8}+\frac {13\,a^2\,b^2}{4}+\frac {17\,a\,b^3}{8}\right )\,{\cos \left (e+f\,x\right )}^3+\left (\frac {7\,a^2\,b^2}{8}+\frac {11\,a\,b^3}{4}+\frac {15\,b^4}{8}\right )\,\cos \left (e+f\,x\right )}{f\,\left (a^7\,{\cos \left (e+f\,x\right )}^4+2\,a^6\,b\,{\cos \left (e+f\,x\right )}^2+a^5\,b^2\right )}-\frac {{\cos \left (e+f\,x\right )}^5}{5\,a^3\,f}-\frac {\cos \left (e+f\,x\right )\,\left (\frac {1}{a^3}-\frac {3\,b^2}{a^5}+\frac {3\,b\,\left (\frac {3\,b}{a^4}+\frac {2}{a^3}\right )}{a}\right )}{f}+\frac {\sqrt {b}\,\mathrm {atan}\left (\frac {\sqrt {a}\,\sqrt {b}\,\cos \left (e+f\,x\right )\,\left (15\,a^2+70\,a\,b+63\,b^2\right )}{15\,a^2\,b+70\,a\,b^2+63\,b^3}\right )\,\left (15\,a^2+70\,a\,b+63\,b^2\right )}{8\,a^{11/2}\,f} \]
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